Geta Brătescu to represent Romania at the 2017 Venice Biennale
It was announced this morning that nonagenarian artist Geta Brătescu has been selected to represent Romania at the 2017 Venice Biennale in May. According to a press release issued by the Romanian Ministry of Culture, Brătescu’s proposal was chosen ahead of two other contending projects in the second round of the selection process.
Born in Ploiești, Romania in 1926, Brătescu is widely considered the grand dame of Romanian art. Having been expelled from the Bucharest Academy of Fine Arts in 1948 by the communist party, she went on to exhibit her work across the globe and in 2008 was awarded the title of Doctor honoris causa by the National University of Arts Bucharest, for her outstanding contribution to contemporary Romanian art.
Represented by Ivan Gallery in Bucharest and Barbara Weiss gallery in Berlin, the artist previously represented Romania in the Venice Biennale in 1960 and participated in the Biennial’s group exhibition curated by Massimiliano Gioni in 2013. Her work straddles drawing, collage, photography, performance, illustration and film.
This year’s Romanian pavilion will be curated by Art Historian and Curator Magda Radu and managed by Corina Bucea. Details of the exhibition will be revealed at a later date.